Question

Fg

Answer 1

this is the equation

Answer 2

This is not an equation... it's 2 letters

Answer 3

F=mg? free fall force? lol?

Answer 4

fg=G m^1m^2/r^2

Answer 5

sorry

Answer 6

much better!!! :) no worries!

Answer 7

that is te equation

Answer 8

so......G is the whole number

Answer 9

trying to get m^2

Answer 10

i multiply the r^2

Answer 11

then i have no idea what to do??!!

Answer 12

when you type m^2, you are saying "m squared", right?

if so, why is m^1m^2 not just m^3?

Answer 13

yup....that is how the problem is.......probably cuz you are trying to find only m^2

Answer 14

also, it's unclear what you are trying to solve for...

And (sorry for the questions...) is this physics? It is written weird for plain math.

Answer 15

ya.......you dont have to be sorry for the questions...thanks for answering my question.......this is physics.......i accidently put math.sorry again

Answer 16

i just need to move the variables to the other side.........elimination

Answer 17

but i dont know like what to do first and things

Answer 18

this still doesn't make sense i'm in physics... If you're looking for

\[m^2\] and using \[m\] , you should already have the value for m -.-

Answer 19

i need to rearrange the equation to solve for the variable -m^2

Answer 20

@Outkast3r09 your show... I'm confused by the presentation... still hoping there is a physics angle to this one. (p.s. thanks! :) )

Answer 21

i am realy sorry.......i got lost.....it is actually m subscript 2

Answer 22

@Outkast3r09 now it's sounding like physics...

Answer 23

ya REALLY SORRY...I DONT GET THIS!!!

Answer 24

so..msubscript 1 an dm subscript 2 is multiplied

Answer 25

the whole number is G..........THE FRACTIONS DEMONINATOR IS R^2

Answer 26

What class is this? Don't worry about the typing for a sec... we're trying to help, but this is confusing...

Answer 27

ok.....so F subscript g = G m subscript 1m subscript 2/r^2

Answer 28

i am just rearranging the variables to find r

Answer 29

alrighty...

Answer 30

G is whole number

Answer 31

\[F _{g} = \frac{ G m _{1}m _{2} }{ r _{2} }\]

Answer 32

Is that close?

Answer 33

r^2..this is my first time using this so i have no idea how you did that?

Answer 34

!!

Answer 35

The equation button below where you are typing... it takes some practice, but it can help when there is confusion :)

Answer 36

an the G is a whole number in the fraction

Answer 37

ok thx

Answer 38

like 4 1/3..its 4

Answer 39

The shorthand is usually fine... BUT!!! x^2 is the short hand for "x squared" not "x subscript 2" so @Outkast3r09 and I were not "speaking your language" :)

Answer 40

lol.ya sorry about that

Answer 41

\[F _{g} = G \frac{ m _{1} m _{2}}{ r _{2} }\]

Answer 42

Is that better? (it's actually equivalent to what I put up earlier.

Answer 43

yes.......r squared

Answer 44

oh

Answer 45

oh, so not "r sub 2" but "r squared" ?

Answer 46

yup

Answer 47

but everything else was correctly written?

Answer 48

yes

Answer 49

and just to be clear, you want to isolate, or solve for, "m sub 2" ?

Answer 50

isolate

Answer 51

so...
1) multiply both sides by "r squared"
to give "Fg * r squared" on the left
and (G * m_1 * m_2) on the right

Answer 52

2) divide both sides by (G * m_1)
to give (Fg * r squared) / (G * m_1) on the left
and m_2 isolated on the right.

Answer 53

dont i divide by G...but ok

Answer 54

\[m _{2} = \frac{ F _{g} r ^{2} }{ Gm _{1} }\]

Answer 55

oh ok

Answer 56

I divided by G and m_1 in a single step... you could do them one at a time.

Answer 57

oh.i was confused at that part..........so you can..

Answer 58

ok thanks so much

Answer 59

If you are more comfortable dividing each one, one at a time, that is totally fine... really!

Answer 60

i would get divided by g divided by m_1

Answer 61

I think that's right, but take another look at the expression I posted above... that had isolated m_2. You might want to do another step or so in the process, but that is the correct end result.

Answer 62

oh ok
i have a question about open study..is this all over the nation?

Answer 63

What do you mean... is it available to people across the country?

Answer 64

nevermind..thankis so much though

Answer 65

yes, it's available everywhere... world wide, as far as I know, at least as long as the other countries are not "blocking" it. But I know students in Canada using it also :)

Glad to help... ask any time (and don't forget to thank your "helpers" with medals :) )

Answer 66

haha i will