Question

Dinitrogen pentoxide can be made by the reaction of nitrogen with oxygen. Consider the reaction
of 35g of nitrogen with 48 grams of oxygen.What is the maximum number of grams of dinitrogen pentoxide that can be made?

Answer 1

I got 270 grams as my answer but the answer is 65 grams. I'm confused

Answer 2

2N2+5O2 --> 2(N2O5)
balance the equation first
convert 35g N2 to moles
convert 48g O2 to moles
find the limiting reagent (which ever has less moles), then mole-ratio to 2(N2O5) and find your mass, hope this helped!

Answer 3

I converted it and got 2.5 mole N2 and 3 moles O2. I found teh limiting reagent to ve N2 since it produces 2.5 moles N205. Then i multiplied 2.5 moles * 108 (the molecular weight) and got 270. Im not sure what I'm doing wrong.

Answer 4

Strange, I got 135g of N2O5

Answer 5

Wow all three of the answers are very different. The answer key says 65, I got 270 and you got 135

Answer 6

make sure you're using N2 molar mass of (14.01*2) and O2 molar mass of (16*2)
35g/28.02g/mol = 1.25 moles N2
48g/32g/mol = 1.406 moles O2
N2 = limiting reagent
mole ratio 1.25 mole N2 = 1.25 mole N2O5 = 1.25 mol * molar mass of N2O5 (14.01*2+16*5) = 135.025
Im pretty sure I did the math right

Answer 7

Ok im going to try it myself also becuase i forgot N2 AND O2 were diatomic. Ughh but why the asnwer is 65...idk :(

Answer 8

Sometimes answer key could be wrong, I really don't see where I could've miscalculated, I've triple checked my work lol

Answer 9

lol thanks :) and yeah i got 135 g too

Answer 10

i think 65 is incorrect. thanks. I'll ask my professor if tehre was a glitch in the asnwer key.

Answer 11

but the weird thing is that when you multiply 108 g by 0.6 mol O2 you actually get 64.8 or 65 grams of N2O5. Are we both not seeing how O2 could possibly be the limiting reagent

Answer 12

But the moles of O2 was more than N2 which made the N2 the limiting reagent

Answer 13

Thats what I thought too...till someone on a discussuion borad wrote O2 is the limiting reagent b/c the ratio of O2 to N2O5 IS 2/5 and the ratio of N2 to N2O5 is 2/2. Does taht make any sense to you?

Answer 14

Ah yes, im sorry, O2 should be the limiting reagent :), forgot to divide because the molar ratios were not 1 to 1. Forgive me it's almost midnight here :)

Answer 15

Yes its almost 1am here too! And sorry to bother you but can you please explain why in this situation we dont look at the moles we ended up with to find the LR but teh ratio of the reactants to teh products?

Answer 16

Limiting reagent you have to divide the moles to find the true ratio

Answer 17

idk what you mean?? srry :/