Question

(2x^3y^0)(4x^0)

Answer 1

do you know what something raised to the "zero power" is?

Answer 2

1

Answer 3

right! good!

So simplify using just that fact... and see what you get...

(2x^3y^0)(4x^0)

= (2x^3)(1)(4)(1) would you agree?

Answer 4

yes.

Answer 5

so, you are almost all the way there....
(2x^3)(1)(4)(1) = 8x^3

Answer 6

oops! I left out a term... hold on...

Answer 7

what happen to y

Answer 8

(2x^3y^0)(4x^0) =

no wait :) I didn't leave out a term....

2x^3 is fine... leave it...

y^0 = 1 .... it "goes away"

4x^0 becomes just 4, because x^0 is just 1

Answer 9

so the product is 2x^3(4) = 8x^3

Answer 10

thanks

Answer 11

glad to help.... good luck

Answer 12

yeah. for this one is it the same as what we just did. 6^0/a^-2

Answer 13

6^0 = 1

a^(-2) is the same as 1/a^2

\[a ^{-2} = \frac{ 1 }{ a ^{2} }\]

Answer 14

so 6^0/a^-2 = (1) / (1/a^2)
= a^2

Answer 15

so 6^0 will it disapear and just be 1/a^2

Answer 16

almost, but it was "divided by a^-2" which is the same as "multiplied by a^2"

Answer 17

k. so it will just be a^2

Answer 18

yes, exactly :) Good work :)

Answer 19

thanks.

Answer 20

1/8z^-9