Question

factor this for me?

Answer 1

\[4u ^{2}v(v+1)+1\]

Answer 2

That's what I got, but I feel like more is needed....

Answer 3

That's about all you can really do with that.

Answer 4

nothing else good job

Answer 5

\[(2u)^2(v^2+v+1)\]
hmm yah there isn't much you can do beyond that.

Answer 6

Oh. Ok, thanks guys. My math teacher (H) told me that if you only do one step, you prolly did it wrong. Bad teacher, then.

Answer 7

Not a bad teacher, just making a generalization. Sometimes generalizations don't exactly apply.

Answer 8

wait, from the 2u^2+1 you can symplify!!!

Answer 9

2u^2 +1^2

Answer 10

oh wait you can't. Only differences. Aww man. Thanks anyway.

Answer 11

\[(2u)^2+1\]
So you have the sum of squares, which won't factor the way you want :( it can be factored into complex conjugates (but I doubt that's what you're working on in class right now :O
If it had been the difference of squares, then yes you maybe could do something with it c: