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Complete the algebra to show that 1−x^−1−(x−1)(x^−2) simplifies to (1−1/x)^2
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\[(1-x^{-1}) - (x-1)(x^{-2})\]Is this your question?
yes
Do you know:\[a^{-1} = \frac{ 1 }{ a }\]Its a index rule.
\[(1-\frac{ 1 }{ x }) - (x-1)(\frac{ 1 }{ x^{2} })\]
\[\frac{ (x-1) }{ x } - \frac{ (x-1) }{ x^{2} }\]\[\frac{ x(x-1) - (x-1) }{ x^{2} } = \frac{ x^{2} -x -x +1 }{ x^{2} } = \frac{ x^{2} -2x +1 }{ x^{2} }\]
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\[\frac{ (x-1)^{2} }{ x^{2} } = (\frac{ x-1 }{ x })^{2} = (\frac{ x }{ x } - \frac{ 1 }{ x })^{2}\]
Finally: \[(1 - \frac{ 1 }{ x })^{2}\]
@ihatemath33 Got it?
yes thank you!!
you are welcomed!
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