Question

Given the following table:

x 0.0068 0.0069 0.007 0.0071 0.0072
f(x) 0.56136243 0.4025256 -0.99636221 0.50259601 0.61217801

Calculate the value of f′(prime) (0.007) to two places of accuracy.

The online question also lets me change the increment value for the data table provided, by changing the value of change.

It also asks:
How will you tell when your increment is small enough to give you a good answer for the problem?

I've tried using the general slope rise-run, but it wouldn't accept my answer as correct, I can't seem to see what I'm doing wrong here.

Answer 1

so there is a zero between x =0.069 and -.007 and then anoth zero exists between 0.007 and 0.0071

so f(0.007) looks like a minimum value as its between 2 zeros...

so f'(0.007) will be an x- intercept on the 1st deriviative graph.

or f(0.007) = 0

Answer 2

Hello, I just tried the answer zero, and the online question rejected the answer, this question is really confusing me

Answer 3

can you understand what I said in my explanation... ?

Answer 4

here is what it looks like..