solve for theta
\[\theta = \theta\]So far with our knowledge, we have the above.
\[\frac{ (2^{-\theta}(\theta+1 }{ \theta-1 }=x\]
\[{2^{-\theta}(\theta + 1) \over \theta -1} = x\]This?
yes
So, the first step will be:\[2^{-\theta}(\theta + 1) = x\theta - x\]
ok then from there
Divide both sides by \(\theta + 1\).\[2^{- \theta} = {x\theta - x \over \theta + 1}\]
Now use logarithms.
ill have \[-\theta \ln (2)=\ln (x)+\ln (\theta-x)-\ln (\theta+1)\]
I don't know.\[-\theta = {\log_2{x\theta - 1 \over \theta + 1}}\]
then how to find it it seems like theta is both sides
That's right... hmm
so does it means we cannot find theta or is there any other method to solve this problem
It's actually a complex number.
hmm i don't know how to solve it using complex number techniques
@REMAINDER
the problem is that they did't give me cos sin tan i have the logarithm of which i don't know how to remove it
but if maybe it was i trig problem have sin cos or tan i can find it so they didn't give me anything that can hlp me to solve for theta
so if you can i think you need seprate theta on one side and after this you will see what you can doing again and how with or wthout logarithm
it is possibill separate it theta on one side how do you think it ?
i've been trying to separate on one side but i don't find it
let theta here đ because i not can writing theta so than there are (đ+1) ----- = xđ -x 2^đ so can you separate it now ?
no i will remain with the same thing i had wen solving using theta
sorry but i need to go now but i will came back and i will solve it in the night bye
ok
@jhonyy9
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