Question

Last question :

Answer 1

Which of the following polynomials below is identical to the polynomial \[(x^2-1)(x^2-4)\]

Answer 2

options are :

a) \[x^4+4\]

b) \[x^2-5x+4\]

c) \[(x^2+1)(x^2+4)\]

d) \[(x^2+x-2)(x^2-x-2)\]

Answer 3

what do u think ? just by looking ?
no solving anything..

Answer 4

one of your options has got no cubic term and it is similar to that of your given equation ..expand your given equation first

Answer 5

\[x^4-5x^2+4=0\] does any of your option look like this..after the expansion

Answer 6

WELL........ TWO POLYNOMIALS ARE IDENTICAL IF THE DIFFERENCE BETWEEN THE POLYNOMIALS IS 0

Answer 7

\[(x^2-1)=(x-1)^2\]
is this right?

Answer 8

nopes

Answer 9

what means nopes

Answer 10

what nopes??

Answer 11

@igbasallote

Answer 12

expand every option and you'll have your answer

Answer 13

but it was right? you did'nt say??

Answer 14

NO...... (x^2 -1) and (x-1)^2 are not identical

Answer 15

@mayankdevnani

Answer 16

since \[(x ^{2}-1)(x ^{2}-4)=((x -1)(x +1)(x-2)(x+2))\]

and

u know that

option d is equal to

\[(x+2)(x-1)(x-2)(x+1)\]
what does it implies?

Answer 17

\[x^2-1^2\]

Answer 18

BECAUSE (x^2-1) -(x-1)^2
=x^2-1-(x^2-2x+1)
=x^2-1-x^2+2x-1
=2x-2
THE DIFFERENCE BETWEEN THE POLYNOMIALS IS NOT O

Answer 19

@REMAINDER

Answer 20

no ,how did u get that?

Answer 21

@mayankdevnani did u understand @REMAINDER

Answer 22

no

Answer 23

HE FACTORED ALL THE TERMS OF ALL OPTIONS AND THE QUESTION

Answer 24

wat i mean is that
by sorting option d
the one i've simplified
u'll have

(x-1)(x+1)(x-2)(x+2) which is equal to the factor of the
\[(x ^{2}-1)(x ^{2}-4)\]

Answer 25

\[answer \] is \[x^2+2x^2+1\]

Answer 26

check this


do u understand this part?