Question

Is the function even, odd, or neither even nor odd?

Answer 1

\[f(x) = 14\sqrt[3]{x}\]

Answer 2

I know that the function is even if f(x) = f(-x), right?

Answer 3

right

Answer 4

So f(-x) = 14^3(sqrt)-x ???

Answer 5

Then the function cannot be even.

Answer 6

Because they are not equal.

Answer 7

Am I really off here?

Answer 8

\[f(-x) = 14\sqrt[3]{-x}=\]

Answer 9

f(-x) = 14^3i(sqrt)x

Answer 10

\[f(-x) = 14^3i \sqrt{x}\]

Answer 11

Is this right?

Answer 12

another trick is to notice the degree of the function

Answer 13

\[\sqrt[3]{-1}=\]

Answer 14

@amistre64 What about the degree of the function?

Answer 15

@UnkleRhaukus Is it -1?

Answer 16

try x(y) instrand of y(x)

Answer 17

What do you mean?

Answer 18

i dont know the cube root of -1 , and i dont know the degree of the equation either

Answer 19

symetric about the origin than its odd, symetric about the y axis than its even, symetric about the xaxis....well then its neither because its not a function at all...think about it.

Answer 20

hmm, my initial thought might not always work out

Answer 21

It's neither? How is it not a function?

Answer 22

y = x^2 is an even function, it has an even degree

y = (x-3)^2 is still an even degree, but because it has been shifted from the origin, its not symetric is it

Answer 23

if something is symmetrical by the x axis that means there are two x inputs...it does not pass the vertical line test...which makes it not a function

Answer 24

a cbrt function is symmetric thru the origin