PRECALCULUS HELP ! help me understand remainder theorem
my notes has : The Remainder Theorems The Remainder Theorem states: If a polynomial f(x) is divided by (x – k), the remainder is r = f(k). This means we can find a point on the graph of a function by choosing a value k for x = k and using division to get a remainder. The remainder will be the y coordinate of the point on the graph. For example: For x = 2 and f(x) = x4 + 2x3 – 4x2 + x - 6, we determined in the previous Test your skills exercise that the remainder was 12. Therefore, there is a point (2, 12) on the graph of the function.
If \(f(x)\) is divided by \(x - k\), then the remainder is \(f(k)\).
why the remainder gives y coordinate ?
yes, why/how... i dont see it
a numerical example or something would help...
Because \(f(2) = 12\), there is a point \((2,12)\) on the graph. Not to think too hard about it!
yay i see !!!!!!! thank you :) thats perfect and to the point explanation ! thnks a lot :)
You're welcome!
since f(2) = 12, if we divide f(x) by (x-2), we get a remainder of 12 !
Yeah, and I know how to derive it, if you want to know...
i would like to go through if u have time and if its easy
\[\text{Dividend = Divisor}\rm \cdot Quotient + Remainder\]Now let's say that the dividend is \(f(x)\), the divisor is \(x - k\), the quotient is \(q\) and remainder is \(R\).\[f(x) = (x - k)\cdot q + R\]What if we substitute \(x\) with \(k\) in the equation?\[f(k) = q(x - x) + R\]\[f(k) = 0q +R\]\[f(k) = R\]
It's really easy, actually!
if R= 0, then (x-k) is a factor of f(x). yesssssssssssssssss its easy now after your explanation ! ty so soo much xD
And that's the factor theorem you were talking about. :)
lol thats coming up next... ;)
when only some right person explains me i learn very fast than on my own :| ima bug u with more tomorrow cya ;P
lol
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