Two positive charges of 6.0 X 10 (exponent of -5) C are separated by 0.50 m. What force exists between the charges ??

Question

anonymous · Answer

use F =kqq/r^2
r=.50m

anonymous · Answer

is that  the answer ?

anonymous · Answer

can u please explain further how u solve it ?

prakharluv · Answer

plz check the magnitude of charge is correct or not...

anonymous · Answer

yes its correct

prakharluv · Answer

so on putting the given data on the equation 
$$F=k \frac{ q _{1}*q_{2} }{ r ^{2} }$$
we can find out the force
F=1296*10^-1N

anonymous · Answer

q1= 6.0 x 10^-5 C,
q2= 6.0 x 10^-5 C
distance= r= 0.50m
Force= (k*q1*q2)/r^2

put the values and get the answer..

anonymous · Answer

gj with those calculators everyone!

anonymous · Answer

k is constant and value of k is 9 x 10^9 Nm^2/C^2

anonymous · Answer

okay so is that the answer - F= 1296*10 ^-1 N ?
so the u wod sole it by doing F = 6.0 x 10( exponent -5) divided 0.50?

anonymous · Answer

give up.