Question

Two positive charges of 6.0 X 10 (exponent of -5) C are separated by 0.50 m. What force exists between the charges ??

Answer 1

use F =kqq/r^2
r=.50m

Answer 2

is that the answer ?

Answer 3

can u please explain further how u solve it ?

Answer 4

plz check the magnitude of charge is correct or not...

Answer 5

yes its correct

Answer 6

so on putting the given data on the equation
\[F=k \frac{ q _{1}*q_{2} }{ r ^{2} }\]
we can find out the force
F=1296*10^-1N

Answer 7

q1= 6.0 x 10^-5 C,
q2= 6.0 x 10^-5 C
distance= r= 0.50m
Force= (k*q1*q2)/r^2

put the values and get the answer..

Answer 8

gj with those calculators everyone!

Answer 9

k is constant and value of k is 9 x 10^9 Nm^2/C^2

Answer 10

okay so is that the answer - F= 1296*10 ^-1 N ?
so the u wod sole it by doing F = 6.0 x 10( exponent -5) divided 0.50?

Answer 11

give up.