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OpenStudy (anonymous):
b^2+16b+1=0
is the answer b=8+3root7?
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mathslover (mathslover):
\[\large{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\]
are you sure that you applied this formula?
OpenStudy (anonymous):
It says complete the square do i still do the quadratic formula?
OpenStudy (radar):
If requests that you complete the square, you should do so. I think you have it almost whipped, check your signs.
OpenStudy (anonymous):
ahh it should be a - 8
mathslover (mathslover):
no if it says complete the square then :
\[\large{b^2+16b+1=0}\]
\[\large{b^2+16b+1+64=0+64}\]
\[\large{(b+8)^2 = 63}\]
\[\large{b = \sqrt{63} -8}\]
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OpenStudy (radar):
I came up with:\[-8\pm3\sqrt{7}\]
mathslover (mathslover):
\[\large{b = -8 \pm \sqrt{63}}\]
\[\large{b = -8 \pm 3\sqrt{7}}\]
OpenStudy (radar):
Note that \[\sqrt{63}=\sqrt{9}\sqrt{7}\]
mathslover (mathslover):
got it @tvise ?
OpenStudy (anonymous):
Yes. When i originally did it i did not isolate the variable so when i re did it i forgot to change signs
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mathslover (mathslover):
no problem, take care of it from now, :)
OpenStudy (radar):
Good luck, and the "signs" can bite you. lol
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