Question

The second of three numbers is 1 less than the first. The third number is 11 less than the second. If the frst number is twice as large as the the third, find the three numbers.

Answer 1

oo system of equations! these are fun :)

Answer 2

So here is our system :o (f=first) (s=second) (t=third)
s=f-1 <-- second number 1 less than the first
t=s-11 <-- third number 11 less than then second
f=2t <-- the first number is twice the third number

So three equations.. hmmmm what can we do :)

Answer 3

Either substitution or elimination will work, are you comfortable with either method? :D

Answer 4

i am not sure i would write three equations, although that would also work
i might call the second number say \(x\)
then the first number is \(x+1\) and the third is
\(x-11\) and you know also that the first number
\(x+1\) is equal to \(2(x-11)\), twice the third number
so you can write
\[x+1=2(x-11)\] and solve for \(x\)

Answer 5

Thanks :)