Question

Chemistry question: What is the mass, in grams, of a sample of 6.12 × 1024 atoms of manganese (Mn)?

6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166 rounded to 10.2
10.2 mol x 54.9380g/1 mol = 558.505 = 559g

I was just wondering if I rounded to high to get the right amount of sig figs? Is my answer correct or should I change it?

Answer 1

I did it again, but I didn't round and this is what I got:
6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166
10.166 mol x 54.9380g/1 mol = 558.499g

Answer 2

i think your right i just did the problem and came up with the same answer ;D

Answer 3

the first one or the second one?

Answer 4

the second one ;D

Answer 5

okay, then I'll go with that one! thank you!

Answer 6

no problemo ;D

Answer 7

I will say though, I think I might have written the second one incorrectly. For some reason, I din't feel like it's written correctly...

Answer 8

don't*

Answer 9

it should be written like this i mole= 588.499g so u wrote it right ;D

Answer 10

doesn't it have to have 3 sig figs though?

Answer 11

so would I just change it to 558g?

Answer 12

im just not sure, I just know my teacher is very strict about sig figs

Answer 13

yes if u need 3 sig figs then 558 would be correct ;D i was just trying to be accurate sorry!!

Answer 14

no no, don't be sorry, I like accuracy! lol :) I just wanted to make sure

Answer 15

Thanks again for ur help!

Answer 16

uh-huh no problem ;D

Answer 17

Okay, yeah so just to clarify, my answer is going to be this:

6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166
10.166 mol x 54.9380g/1 mol = 558.499 = 558g :)

Answer 18

yea thats right ;D

Answer 19

okie dokie! :D