Question

write an equation in slope-intercept form of the line that is perpendicular to the graph of each equation and passes through the given point.

1. y=-5x+1; (2,-1)

2. 3x-4y=2; (6,0)

Answer 1

@experimentX

Answer 2

compare this with
y=mx+c

your line would be
y = -(1/m)x + b

put those values of x and y and get value of b.

Answer 3

yea i know that part its just some part that am stuck at cause of the fraction

Answer 4

y=-5x+1;
y=mx+c
--------
m=-5

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your line would be
y = -(1/(-5))x + b
y = (1/5)x + b

put this (x,y) = (2,-1)
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(-1) = (1/5)(2) + b
b = -1 - 2/5 = -7/5

so you line is
y = x/5 -7/5

Answer 5

yea if it wasn't in the slope of a perpendicular, because the lines are negative reciprocal of each other

Answer 6

so for example y=-7x+2 the new perpendicular slope would be 1/7

Answer 7

yeah ...just change it
3x-4y=2
4y = 3x - 2
y = 3/4 x - 2/4
y = mx + c
m = 3/4 and c=-2/4

Answer 8

yes ... it would be

Answer 9

wait is that the working out for the second one and do understand what am saying cause i might not explain things so good

Answer 10

yeah ... I"m understading.

Answer 11

ok, so are you gonna work it out step by step for me?

Answer 12

this is similar to the first one. try this one ... for pratice. I'll see if you are correct or not.

Answer 13

ok well i got a different answer i got -4y=-3x+2 i subtracted 3x from both side

Answer 14

http://www.wolframalpha.com/input/?i=line+perpendicular+to+3x-4y%3D2+at+%286%2C0%29

Answer 15

you should get
y = 8-(4/3)x

Answer 16

ok i'll try and see how to do that, even though am not sure how to

Answer 17

3x-4y=2
4y = 3x - 2
y = 3/4 x - 2/4
y = mx + c
m = 3/4 and c=-2/4

so -1/m = -4/3

so your line should be
y = -4/3 x + b

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put (x,y) = (6,0) and get the value of b. put that value of b in above equation and get your answer.

Answer 18

ok thanks, and that's the same way for the first one too