Question

k^2+4k=96 trinomials

Answer 1

you need to set up your problem the right way.First off you need to subtract 95

So it looks like this K^2 +4K -96 = 0

You must factor

Answer 2

but that the thing im so confused where do i start first like how do i do it

Answer 3

You could use the COMPLETING THE SQUARE method
k^2+4k=96
add 2^2 to both sides
k^2 + 4k + 2^2 = 96 + 2^2
LHs becomes a perfect square (k + 2)^2, so we get
(k + 2)^2 = 96 + 4
taking square root of both sides
k + 2 = +/- sqrt(100)
k = -2 +/- 10
so k = -2 - 10 = -12
or
k = -2 + 10 = 8

Answer 4

For factorising, first rearrange the equation to read
K^2 +4K -96 = 0

Now find factor pairs of -96 (i.e. constant at the end) and select the pair whose product is - 96 sum is + 4 (coefficient of the x-term )
-1 x 96 or 1 x -96
-2 x 48 or 2 x -48
-3 x 32 or 3 x -32
-4 x 24 or 4 x -24
-6 x 16 or 6 x -16
-8 x 12 or 8 x -12

Out of these we find the pair -8 x 12 = -96 and -8 + 12 = +4
so we split the middle term as follows
k^2 -8k + 12k - 96 = 0
k(k - 8) + 12(k - 8) = 0
(k - 8)(k + 12) = 0
using zero product property
if k - 8 = 0, then k = 8

if k + 12 = 0, then k = -12