Let f(x) = 5x + 12. Find f–1(x) 12x + 5 1/5x+12 5/x-12 x-12/5
By f-1(x) you mean the inverse I assume. To do that just swap the values of your function with y<->x. y=5x+12 becomes x=5y+12 and now solve for y.
wut? this is confusing
Do you know how to solve the equation for y, that means to rearrange the equation I have given, x=5y+12 to have y alone and all the numbers on x's side.
let me see,
one moment
y=5x+12?
isnt that what is up their ??
No man.. you need to do algebraic operations. To get 12 on the other side, you need to subtract 12 from both sides, so you will have, x-12 =5y Now what do you do with the 5 that is multiplying y. How do you move that from the right side to the left side?
oh man this is tuff, i remember learning this last year.
hold on
Dude, this is as easy as math gets.. It aint tuff.. trust me.
i give up, though, I was thinking this, 5y+x=12
What grade are you on?
junior, but I failed segment 2 of algebra in my sophomore year bc i slacked off
i guess you have the right to tell me im dumb
no dude you're not dumb, I just wanted to know how to explain the problem to you. Alright, check this out. x-12=5y You divide both sides by 5 because that number is multiplying y on the right side. So when you divide both sides you will cancel out the one that's multiplying y and. Therefore your equation now becomes, x/5 - 12/5 = y That is the inverse of your initial function
oh, i get it
how would i solve for this question?
Are those the only possibilities that you have?
yep
None of them are correct.
which one would be the closest?
if you had something like 1/5x - 12/5, that would be the closest
ill just guess. Thanks for your help though!
lol, sure you're welcome.
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