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Mathematics 9 Online
OpenStudy (anonymous):

Let U, the universal set, consist of all the positive rational numbers (or fractions). Let A be the set defined by A = {p/q | p,q are odd naturals and q is nonzero}. Find a set B that satisfied the following 3 conditions: 1) B is a subset of A', the complement of A. 2) B has exactly 255 proper subsets. 3) No element of B is greater than 1.

OpenStudy (anonymous):

well, 8 elements are in set B, since to have 255 proper subsets, the set must contain n elements where 2^n-1=255

OpenStudy (anonymous):

so any 8 fractions p/q which where p,q are even naturals and q is nonzero would work

OpenStudy (anonymous):

and p<q

OpenStudy (anonymous):

how do you know what set b is? and how there are 8 elements?

OpenStudy (anonymous):

B has exactly 255 proper subsets. implies there are 8 elements

OpenStudy (anonymous):

set B could be any set, since the question states that Find a set B that satisfied the following 3 conditions:

OpenStudy (anonymous):

so how do i find set b?

OpenStudy (anonymous):

any set with 8 fractions p/q where either p or q are not odd naturals and q is nonzero and p<q example {1/3,3/5,5/7,7/9,9/11,11/13,13/15,15/17}

OpenStudy (anonymous):

ok so thats the answer to the question all these fractions?

OpenStudy (anonymous):

yep, any other 8 fractions that satisfy the description would also work

OpenStudy (anonymous):

ok great what does is mean that b is the subset of a '?

OpenStudy (anonymous):

yes, B is the subset of A' which is the compliment of A

OpenStudy (anonymous):

but what does that have to do with the question?

OpenStudy (anonymous):

The questions is asking you to find a subset of A', that has 8 elements, and each element is less than 1

OpenStudy (anonymous):

and all elements have to be positive rational numbers since B is also a subset of U

OpenStudy (anonymous):

ok thank you for your help!! i really appreciate it!

OpenStudy (anonymous):

np

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