Question

zero exponent property
(2x^2y^-3/-12z^-1)^0

Answer 1

Know that a^0 = 1

Answer 2

so all equals 1?

Answer 3

(2x^2y^-3/-12z^-1)^0 = 1

Answer 4

can i show u another problem?

Answer 5

yep, bearsams

Answer 6

no problem

Answer 7

(-9x^-3z^4/6y^6)^0 (-2x^2)^3

Answer 8

Anything to the zero power is just one. It's the Law — the Laws of Exponents

Answer 9

Are they two different terms?

Answer 10

yah but 1 problem

Answer 11

Then (-9x^-3z^4/6y^6)^0 (-2x^2)^3 = 1{(-2 x -2 x -2)(x^2)(x^2)(x^2)}
= -8x^6

Answer 12

Are you okay with that problem?

Answer 13

im sorry but i dont know how to do that

Answer 14

In indices, \[a^m \times a^n= a^\left( m+n \right)\]

Answer 15

This implies \[(-2)^3 = -2\times-2\times-2=-8\]

Answer 16

Also, \[x^2\times x^2\times x^2 = x^\left( 2+2+2 \right)\]
which equals \[x^6\]