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Find f' and f'' y=(6x^5/5)-7x
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\[y=\frac{ 6x^5 }{ 5 }-7x\]\[=\frac{ 6 }{ 5 }x^5-7x\] Does it help if you can look at it like this maybe? Both of these you need only apply the power rule, need some help with that? :D
f' of 6/5 x^5 is 6x^4 and f' of -7x is just 7 right?
very good :) one minor error, the derivative of -7x = -7
D'oh!! oh yea
gonna take a shot at f''? :D
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so f'= -42x^5 + 6/5x^5 - 7?
whu? :o
\[f'(x)=6x^4-7\] You already found this :) now try to find f''(x).
f''= 24x^3
yay gj c:
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thanks!! i have to remember that way to write the fraction, it was throwing me off
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