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Three blocks of masses 1.0, 2.0, and 4.0 kilograms are connected by massless strings, one of which passes over a frictionless pulley of negligible mass, as shown below. Calculate The acceleration of the 4.0 kilogram block.
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4g-T=4a T-3g=3a 4g-(3g+3a) = 4a g=7a a=g/7
@Algebraic! Where did you get T - 3g = 3a
The acceleration and tension is the same on the left?
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|dw:1348708422277:dw|
sum of forces = ma
T-3g =3a
try to do all your pulley problems like that. much easier when direction is always consistent.
|dw:1348708601533:dw|
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