Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Rewrite the following definition as a biconditional: Points that lie on the same line are collinear.

Directrix (directrix):

Do you know how to write "Points that lie on the same line are collinear." in the If, then" format?

OpenStudy (anonymous):

yeah

Directrix (directrix):

So how would it read? What we need to do is to get P->Q and then its converse to form the biconditional.

OpenStudy (anonymous):

"if points lie on the same line, then they are collinear" tada lol

Directrix (directrix):

P: if points lie on the same line q:then they are collinear That's p>q Okay, how would the converse of p->q be written?

OpenStudy (anonymous):

thats what i dont know :/

OpenStudy (anonymous):

wait does it go " if they are collinear then the points are on the same line"?

Directrix (directrix):

The converse of p-> q is q ->p. Look above where I wrote the designations for p and q. Then, write If the q part, the the p part. That would be the converse.

Directrix (directrix):

Definition: A biconditional statement is defined to be true whenever both parts have the same truth value. The biconditional operator is denoted by a double-headed arrow . The biconditional p<->q represents "p if and only if q," where p is a hypothesis and q is a conclusion.

Directrix (directrix):

wait does it go " if they are collinear then the points are on the same line"? ------------ YES, that's correct. Read the definition of biconditonal and we can wrap up this problem.

Directrix (directrix):

Note on "if they are collinear then the points are on the same line"?" Not only is it the correct form of the converse, it is a true statement as is the original statement. So .... it's a biconditional.

OpenStudy (anonymous):

k

Directrix (directrix):

Biconditional Form: Points on the same line <--> ? You add the second part.

OpenStudy (anonymous):

are collinear

Directrix (directrix):

Points on the same line <--> collinear points. That's how I would phrase it.

OpenStudy (anonymous):

thanks for your help! :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!