Stuck again. Same concept.
Ingrate the following equation---

Question

anonymous · Answer

$$3\int\limits \frac{ 1 }{ x^2 + 2x -5}$$
I need to get it to 1/x^2 + 1 form.

anonymous · Answer

I believe completing the square may be necessary? I don't know... our middle school algebra in which we were to learn that basic stuff was pretty much worthless

anonymous · Answer

yes i would go for completing the square i guess

anonymous · Answer

not seeing how that would be beneficial, though, because it's (x+1)^2 - 6..... not sure where to go from there....

anonymous · Answer

mm because of this minus right ?

anonymous · Answer

..... because then 1/(x - 1)^2 - 6 has to become 1/x^2 + 1
Not liking the (x-1)^2 thing going on....

anonymous · Answer

+5

anonymous · Answer

(x+1)^2 +4

anonymous · Answer

Algebraic! - there is -5 there

anonymous · Answer

nope

anonymous · Answer

what about :

$$\int\limits_{}^{} \frac{ dx }{ x^2-a^2 } =\frac{ 1 }{ 2a } \ln \frac{ x-a }{ x+a }$$

anonymous · Answer

Well according to Maple, which we were to use to find the correct answers so we could compare ours..... there needs to be an arctan in the final answer, and a natural log.... I already got the natural log from a separate part of the problem which I did not include here.... so all I have left is to try to get to the following piece====$$-\frac{ 3 }{ 2 }\tan^-1{\frac{ 1 }{ 2 }}x + \frac{ 1 }{ 2 } $$

anonymous · Answer

The above is what I need to get from the integral I typed for this question...

anonymous · Answer

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        u  r super funny

anonymous · Answer

+5

anonymous · Answer

http://openstudy.com/study#/updates/5063f355e4b0583d5cd3b67e

anonymous · Answer

you mean that he copied the original question wrong ?

anonymous · Answer

aselja;dlkgfjalsdkjgaldgj Apparently.

anonymous · Answer

Lemme try squarin again

anonymous · Answer

did it for you.

anonymous · Answer

wait lol i dont get it .. the denumerator should be x^2+2x +5

anonymous · Answer

?

anonymous · Answer

Yeahhhhhhhhh. I think I miswrote it as I'm taking notes here and just kept on going with it.

anonymous · Answer

lol .. with that i cant compete

anonymous · Answer

So now we're dealing with (x + 1)^2 +4  in the denumerator which needs to become x^2 +1
Annnnnnd the only one helping left. Wonderful.

hartnn · Answer

take 4 common
 u get 4((x+1)^2/4+1) = 4 (((x+1)/2)^2+1)
now put y= (x+1)/2
u get the form 
4(y^2+1)

anonymous · Answer

I had to start completely over.... but I figured it out and am onto the next problem.

hartnn · Answer

ok.