OpenStudy (anonymous):

How will I integrate (cosx)^4 from 0 to pi/4 ?

5 years ago
OpenStudy (anonymous):

\[\int\limits_{0}^{\pi/4}(\cos^2 x)^{3/2}cosx dx \]

5 years ago
OpenStudy (anonymous):

\[\int\limits_{0}^{\pi/4}(1-\sin^2 x)^{3/2} \cos x dx\]

5 years ago
OpenStudy (anonymous):

sin x =t dt = cosx dx Hence \[\int\limits_{}^{}(1-t^2)^{3/2}dt\]

5 years ago
OpenStudy (anonymous):

Actually, that's the problem. I don't remember the technique to integrate such radical expressions . :( .Please can you write a few more steps.

5 years ago
OpenStudy (anonymous):

I would use|dw:1348736256044:dw|

5 years ago
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