Question

How will I integrate (cosx)^4 from 0 to pi/4 ?

Answer 1

\[\int\limits_{0}^{\pi/4}(\cos^2 x)^{3/2}cosx dx \]

Answer 2

\[\int\limits_{0}^{\pi/4}(1-\sin^2 x)^{3/2} \cos x dx\]

Answer 3

sin x =t
dt = cosx dx

Hence

\[\int\limits_{}^{}(1-t^2)^{3/2}dt\]

Answer 4

Actually, that's the problem. I don't remember the technique to integrate such radical expressions . :( .Please can you write a few more steps.

Answer 5

I would use