Question

Show that\[p \nu(p {\Lambda}q)=p\] Hint: no need off table.

Answer 1

\[\vee , \wedge\]?

Answer 2

OR and AND respectively

Answer 3

de morgan's theorem ?

Answer 4

Open the brackets by distributive abd get
p or p) AND (p or q) = p AND whatever = p

Answer 5

of course distributive in Boolean is called De-Morgan's th.

Answer 6

thought so

Answer 7

Not that way@mikael@hartnn

Answer 8

was this your question ?
\[p\vee(p\wedge q)=p\]

Answer 9

yape