OpenStudy (anonymous):

Show that\[p \nu(p {\Lambda}q)=p\] Hint: no need off table.

5 years ago
OpenStudy (unklerhaukus):

\[\vee , \wedge\]?

5 years ago
hartnn (hartnn):

OR and AND respectively

5 years ago
hartnn (hartnn):

de morgan's theorem ?

5 years ago
OpenStudy (anonymous):

Open the brackets by distributive abd get p or p) AND (p or q) = p AND whatever = p

5 years ago
OpenStudy (anonymous):

of course distributive in Boolean is called De-Morgan's th.

5 years ago
hartnn (hartnn):

thought so

5 years ago
OpenStudy (anonymous):

Not that way@mikael@hartnn

5 years ago
OpenStudy (unklerhaukus):

was this your question ? \[p\vee(p\wedge q)=p\]

5 years ago
OpenStudy (anonymous):

yape

5 years ago
OpenStudy (unklerhaukus):

|dw:1348738567670:dw|

5 years ago
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