Question

if
x=1 , 2 , 3, 4, 5
y=7 , 16, 28 , 43, 62
whats the equation, please

Answer 1

Let us assume the equation is y=mx+c.
Plugging in the first values
7=m*1+c
7=m+c
7-m=c
Plugging in the second values
16=m*2+c
16=2m+c
16-2m=c
7-m=16-2m
solve for m.
Then substitute the value of m in
7-m=c
to find c.
After finding both m and c check if other values given satisfy ur equation.

Answer 2

It's not linear, actually a quadratic

Answer 3

ya u r right. @ash2326. I see tht other values given do not satisfy the eqn

Answer 4

@ash2326 , how did u get quadratic ?
if last value was 61, then it would have been quadratic....i think this is exponential or something.....

Answer 5

nopes, its 2nd differences are 3,3,4....so higher differences are not constant, thats why it cannot be x^(something)...it might be (something)^x
@ajprincess u were telling ?

Answer 6

i mean y=a^x+c

Answer 7

I tried with the quadratic form bt did nt succeed. maybe u r right. I am not gud with finding exponential eqns. thanx a lot for clearing that up @hartnn

Answer 8

u would have got a quadratic equation if last value was 61....
2nd differences would have been constant,3,3,3 and it would have been polynomial of degree 2