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Mathematics 17 Online
OpenStudy (unklerhaukus):

graph\[\sin (y) =\sin (x)\]

OpenStudy (anonymous):

Well, that's gonna look awesome. Take the arcsin on both sides, and you get, y = arcsin(sin(x)) Are you supposed to graph this by hand or how?

OpenStudy (anonymous):

they undo each other, dont they. the arcsin and sin

hartnn (hartnn):

|dw:1348749590274:dw|

OpenStudy (anonymous):

Yeah you need to make sure you dont screw up at pi, 2pi, and so on.

OpenStudy (unklerhaukus):

are there more solution curves

OpenStudy (anonymous):

isnt it just y=x as the 2 functions cancel out.

OpenStudy (anonymous):

Here's a relation between sin, arcsin(sin(x)) and x

hartnn (hartnn):

whats the max amplitude and how do we get it analytically ?

hartnn (hartnn):

pi/2 ?

OpenStudy (unklerhaukus):

\(\arcsin n\) returns one value for many values of \(n\)

hartnn (hartnn):

yes,cos its periodic with period 2pi

OpenStudy (anonymous):

CAN SOMEONE EXPLAIN ME WHY IT IS NOT SAME AS y=x

hartnn (hartnn):

in the range pi/2 to 3pi/2, sin is negative

OpenStudy (anonymous):

Take the dev of sin(x), which is cos(x), and for every zero of cos, you have the max and min of sin.

OpenStudy (ash2326):

@heedcom we are tempted to just cancel and simplify it as y=x but this is not that simple cause the range of arc sin is \(\large\frac{-\pi}{2}, \frac{\pi}{2}\) if x is in this range we'd get y=x but supposedly x=pi \[y=\arcsin(\sin \pi)\] \[y=\arcsin(0)=0\ne \pi\] @sauravshakya

hartnn (hartnn):

so it will be y=-x in the range pi/2 to 3pi/2 got this @sauravshakya

OpenStudy (anonymous):

You see the Forward Function is NOT 1:1 - so the Inverse function , strictly speaking does NOT Exist @sauravshakya

OpenStudy (unklerhaukus):

i never said it was a function

OpenStudy (ash2326):

\[y=\sin (\arcsin x)=x\] this is always true

OpenStudy (anonymous):

It is like the equation \[ x^2 = y^2\]

OpenStudy (unklerhaukus):

can you graph the solutions Mikael ?

OpenStudy (anonymous):

OH...... got it. THANX @ash2326

hartnn (hartnn):

are my and @gezimbasha graphs correct ?

OpenStudy (anonymous):

sure, thanks

OpenStudy (anonymous):

Yes @UnkleRhaukus |dw:1348750437001:dw|

OpenStudy (anonymous):

Here you go, the green one is cos(x). You can see there's stops at every pi/2 and 3pi/2, those are cos(x) zeros.

OpenStudy (unklerhaukus):

the graphs so far are only part of the solution set

OpenStudy (anonymous):

For the problem discussed here the graphs are separate points with periodic repetition|dw:1348750632971:dw|

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