graph\[\sin (y) =\sin (x)\]
Well, that's gonna look awesome. Take the arcsin on both sides, and you get, y = arcsin(sin(x)) Are you supposed to graph this by hand or how?
they undo each other, dont they. the arcsin and sin
|dw:1348749590274:dw|
Yeah you need to make sure you dont screw up at pi, 2pi, and so on.
are there more solution curves
isnt it just y=x as the 2 functions cancel out.
Here's a relation between sin, arcsin(sin(x)) and x
whats the max amplitude and how do we get it analytically ?
pi/2 ?
\(\arcsin n\) returns one value for many values of \(n\)
yes,cos its periodic with period 2pi
CAN SOMEONE EXPLAIN ME WHY IT IS NOT SAME AS y=x
in the range pi/2 to 3pi/2, sin is negative
Take the dev of sin(x), which is cos(x), and for every zero of cos, you have the max and min of sin.
@heedcom we are tempted to just cancel and simplify it as y=x but this is not that simple cause the range of arc sin is \(\large\frac{-\pi}{2}, \frac{\pi}{2}\) if x is in this range we'd get y=x but supposedly x=pi \[y=\arcsin(\sin \pi)\] \[y=\arcsin(0)=0\ne \pi\] @sauravshakya
so it will be y=-x in the range pi/2 to 3pi/2 got this @sauravshakya
You see the Forward Function is NOT 1:1 - so the Inverse function , strictly speaking does NOT Exist @sauravshakya
i never said it was a function
\[y=\sin (\arcsin x)=x\] this is always true
It is like the equation \[ x^2 = y^2\]
can you graph the solutions Mikael ?
OH...... got it. THANX @ash2326
are my and @gezimbasha graphs correct ?
sure, thanks
Yes @UnkleRhaukus |dw:1348750437001:dw|
Here you go, the green one is cos(x). You can see there's stops at every pi/2 and 3pi/2, those are cos(x) zeros.
the graphs so far are only part of the solution set
For the problem discussed here the graphs are separate points with periodic repetition|dw:1348750632971:dw|
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