Question

Two blocks connected by a rope of negligible mass are being dragged by a force at a 25° angle above horizontal (see figure below). Suppose F = 105.0 N, m1 = 10.0 kg, m2 = 22.0 kg, and the coefficient of kinetic friction between each block and the surface is 0.150. Find the acceleration of the system and the tension in the rope

Answer 1

First treat the two-block system as one system

Horizontally

Fcos(theta) - (mu)(m1+m2)(N)=(m1+m2)a

and vertically

(m1+m2)g = N + Fsin(theta)

Answer 2

eliminate N and find a

Answer 3

get it?

Answer 4

For Body 1:

\[Fcos \Theta-\mu(mg - Fsin \Theta)-T = ma\]

For Body 2 :

\[T - \mu mg = ma \]

Answer 5

Just Substitute The Given Info..And u have it..)

Answer 6

@stroodles77 Did u understand..)