Mathematics
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OpenStudy (anonymous):
Help with understanding a concept involving the graph of a function.
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OpenStudy (anonymous):
what concept?
OpenStudy (anonymous):
OpenStudy (anonymous):
So the graph x^2+y^2=1 does not describe y as a function of x.
OpenStudy (anonymous):
why not?
ganeshie8 (ganeshie8):
yes it doesnt so what ?
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OpenStudy (anonymous):
But if we localize the view to certain areas (the circles areas), we can see the graph of a function.
OpenStudy (anonymous):
I'm lost on why the areas at x=1 and x=-1 are not graphs of functions, while the other two points are.
OpenStudy (anonymous):
x^2 + y ^2 = 1 means y ^2 = 1 - x^2, right?
ganeshie8 (ganeshie8):
actually you saying it in reverse
ganeshie8 (ganeshie8):
it meets the requirements of function, only at x = -1 and x = 1
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ganeshie8 (ganeshie8):
everywhere else, it fails the vertical line test
OpenStudy (anonymous):
Hm, my teacher is saying otherwise I think.
OpenStudy (anonymous):
x^2 + y^2 = 1 is a curve on a graph such that every point on that curve, when squared and added results in the number 1.
OpenStudy (anonymous):
can you think of any point that would solve this condition?
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OpenStudy (anonymous):
Hmm
OpenStudy (anonymous):
0 and 1?
OpenStudy (anonymous):
very good. what does 0 and 1 mean on a graph? where is the point (0,1) lie on the graph?
OpenStudy (anonymous):
On the x-axis?
OpenStudy (anonymous):
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OpenStudy (anonymous):
Oh, snap, yeah, y-axis. I knew that lol
OpenStudy (anonymous):
no 0,1 means 0 in the horizontal direction and 1 in the vertical direction
OpenStudy (anonymous):
okay. now, can you think of any other point?
OpenStudy (anonymous):
0 and -1?
OpenStudy (anonymous):
very good.
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OpenStudy (anonymous):
|dw:1348768963041:dw|
OpenStudy (anonymous):
any other point?
OpenStudy (anonymous):
(1,0) and (-1,0)?
OpenStudy (anonymous):
yup.
OpenStudy (anonymous):
But how does all this translate to those points not being functions on the graph?
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OpenStudy (anonymous):
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