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Mathematics 10 Online
OpenStudy (dls):

Limits.

OpenStudy (dls):

\[\lim_{x \rightarrow 0}\frac{\sqrt{a+x}-\sqrt{a}}{\sqrt{a(a+x)}}\]

OpenStudy (dls):

After rationalizing,I got, \[\frac{x}{\sqrt{a(a+x)}(\sqrt{a+x} +{\sqrt{a}}}\]

OpenStudy (dls):

@Vikt0r

OpenStudy (anonymous):

im not this smart lol what was the problem

OpenStudy (dls):

:/

OpenStudy (dls):

scroll!

OpenStudy (dls):

@ChmE @Lukecrayonz

OpenStudy (lukecrayonz):

Calc 1?

OpenStudy (dls):

1?

OpenStudy (lukecrayonz):

The levels of calculus, nevermind :P

OpenStudy (dls):

lol

OpenStudy (anonymous):

lim x->0[sqrt(a+x)-sqrta]/[sqrt(a(a+x))]=0 you can sub directly x=0 here

OpenStudy (lukecrayonz):

\[(\sqrt(a+(0)-\sqrt(a))/a\]

OpenStudy (lukecrayonz):

Probably not right but you know I tried

OpenStudy (dls):

lol yeah

OpenStudy (anonymous):

lim x->0[sqrt(a+x)-sqrta]/[sqrt(a(a+x))] \[limx->0\frac{ x }{ (a+x)\sqrt{x } +a \sqrt{a+x}}=0\]

OpenStudy (anonymous):

the numerator is x so x=0

OpenStudy (anonymous):

then the limit=0

OpenStudy (dls):

no..

OpenStudy (dls):

The answer is: \[\frac{1}{2}^{-3/2}\]

OpenStudy (dls):

1/2a^-3/2* a is there too*

OpenStudy (dls):

letsleavethis..

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