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Mathematics
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Limits.
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\[\lim_{x \rightarrow 0}\frac{\sqrt{a+x}-\sqrt{a}}{\sqrt{a(a+x)}}\]
After rationalizing,I got, \[\frac{x}{\sqrt{a(a+x)}(\sqrt{a+x} +{\sqrt{a}}}\]
@Vikt0r
im not this smart lol what was the problem
:/
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scroll!
@ChmE @Lukecrayonz
Calc 1?
1?
The levels of calculus, nevermind :P
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lol
lim x->0[sqrt(a+x)-sqrta]/[sqrt(a(a+x))]=0 you can sub directly x=0 here
\[(\sqrt(a+(0)-\sqrt(a))/a\]
Probably not right but you know I tried
lol yeah
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lim x->0[sqrt(a+x)-sqrta]/[sqrt(a(a+x))] \[limx->0\frac{ x }{ (a+x)\sqrt{x } +a \sqrt{a+x}}=0\]
the numerator is x so x=0
then the limit=0
no..
The answer is: \[\frac{1}{2}^{-3/2}\]
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1/2a^-3/2* a is there too*
letsleavethis..
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