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dy/dt = y(1-y)-hy Suppose that y(0) = y naught > 0 Solve IVP .
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separation of variables works...
dy divides through .. but how does that look as integration
\[\int\limits_{ }^{ } \frac{ dy }{ y(1-y-h) } = t+C\]
I simplified a bit.
could you possibly just show me where you simplified? thats part i'm having trouble with i think
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so we're just integrating the function (y(1-y-h))^-1
right?
yes
which is just ... ln|y(1-y-h)| ?
over h-1?
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how's it coming?
hmm... integral du/u = ln(u) but here, what would you pick for u? if you pick y(1-y-h), as you did, then du = ?
wait why are we working with du now?
hey!
hey. got it yet?
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nooo!!! :( please help
|dw:1348782655032:dw| Then from here, apply a Bournoulli Substitution, have you learned that yet? :o
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