Question

64^(x-4)=4^2x

Answer 1

\[64^{(x-4)}=4^{2x}\]

Answer 2

\[4^{3(x-4)}=4^{2x}\]
\[3(x-4)=2x\]
\[3x-12=2x\]
from here solve for x

Answer 3

@REMAINDER How did you get the 3?

Answer 4

Because 4^3 = 64

Answer 5

But thats a 2

Answer 6

Oh wait nevermind

Answer 7

he simply changed 64 into a base of 4 so that the exponents would have to equal each other.

Answer 8

Ok so the final answer is 12=x?

Answer 9

Go back to the original equation and substitute 12 for x and see if it is the right answer.

Answer 10

Ok.

Answer 11

Yep :)

Answer 12

Thanks!