Question

Let f(x)=5x^(2)

Part 1
Compute the slope of the secant line joining the point of the graph of F whose x coordinates are x=-9 and x=-8.9.

Why I got 89.5?
I know somethings is wrong, Please help!!

Answer 1

f(x)=5x^(2)

f(-9)=5(-9)^(2)

f(-9)=405

Answer 2

f(x)=5x^(2)

f(-8.9)=5(-8.9)^(2)

f(-8.9)=396.05

Answer 3

The slope of the secant line joining the point of the graph of F whose x coordinates are x=-9 and x=-8.9 is then...

m = ( f(x2) - f(x1) )/(x2 - x1)

m = ( f(-9) - f(-8.9) )/(-9 - (-8.9))

m = ( 405 - 396.05 )/(-9 - (-8.9))

m = -89.5

Answer 4

So you lost a negative sign somewhere

Answer 5

Yeah, I have to go back!!! I appreciate... Thank you!!

Answer 6

np

Answer 7

Quick question??

Answer 8

what's that

Answer 9

What will be the tangent of the graph if x=-9
It asking me to compute the slope i put =405 and it said is wrong

Answer 10

find the slope of the secant line from x = -9 to x = -8.99

then

find the slope of the secant line from x = -9 to x = -8.999

keep dragging that second point closer and closer to x = -9

As the second point gets closer to x = -9, the secant line slowly becomes the tangent line (to x = -9)

Answer 11

Ok, so the answer can x=-9?

Answer 12

no, the answer is not -9

Answer 13

I have to graph it then.?

Answer 14

no, you basically just need to compute the slopes of the secant lines above

Answer 15

the slopes will slowly approach the slope of the tangent line at x = -9

Answer 16

Now I am confuse, cause I got the other answer right! and it was the same as this one. :(

Answer 17

can you imagine a secant line going through x = -9 and x = -8.9 ?

Answer 18

No, I looking for more info trying to understand.. please help!

Answer 19

Ok say we have the graph (this is just some arbitrary graph)

Answer 20

Now say we have the point A on the graph