Determine the period of amplitude of y=-cos (x/11+pi/4).

Question

jim_thompson5910 · Answer

Hint:

Given

y = A*cos(Bx + C) + D

The amplitude of the trig function above is |A|

The period is 2pi/B

anonymous · Answer

I just realized that I need to to use that formula...THANKS

anonymous · Answer

I have to learn long form...it's taking me a bit.

jim_thompson5910 · Answer

just keep at it and you'll get it

anonymous · Answer

OK

anonymous · Answer

OK, my professor likes to use y=a(x-h)sqaured
then and we just use the word marks rather than plot points...it's easier.

anonymous · Answer

opps y=a(x-h) squared +k

jim_thompson5910 · Answer

that's a quadratic function (in vertex form), while the original question is a trig function, so they are two completely different problems

anonymous · Answer

oh rats...hmm maybe he just uses it or showed us the similarities. But, I know I need to make a table of the x/ys.

anonymous · Answer

dur...I am looking at a sin question...the one I put up there is COS...

anonymous · Answer

yes

anonymous · Answer

OK, so now I need to try this again...y=cos(3x/4+pi/4) Determine the period and amp.

anonymous · Answer

I meant" y=4cos(3x/4+pi/4).

anonymous · Answer

(Bx+C)=0.   SO, B is where it starts.

anonymous · Answer

Amplitude is 4.

anonymous · Answer

Period is 8pi/3.