arctan((sqrt(3))/3)
\[\tan^{-1} \frac{ \sqrt{3} }{ 3 }\] This is the same as writing: \[\tan \theta= \frac{ \sqrt{3} }{ 3 }\] This is one of your special angles, do you remember the value? :) It's somewhere in the first quadrant.
since when is arctan the same as tan?
Arctan is the inverse function of the tangent function. It can be written this way: \[\tan^{-1} \frac{ \sqrt{3} }{ 3 }=\theta\] When you take the inverse of this, it means you SWAP the terms So the sqrt term, and the (theta) will switch places. And then you change Arctan to Tan. I know it's a lil tricky to understand :C
so once you flip it then what
|dw:1348787236820:dw| Then you're suppose to remember which angle has a tangent of this particular value. It's a special angle :) it's one of these 5 values. \[0, \frac{ \pi }{ 6 }, \frac{ \pi }{ 4 }, \frac{ \pi }{ 3 }, \frac{ \pi }{ 2 }\] Have any idea which one it is? :)
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