Question

if 10x198=(10xm)-(10x2) what is the value of m?

Answer 1

can you see a common factor on the right-hand-side of the equals sign?

Answer 2

no new to this

Answer 3

what number appears in both terms on the right-hand-side?

Answer 4

this is the way question is

Answer 5

I know, I am asking you a question in order to help guide you to the answer.

so, can you spot what number appears in both terms on the right-hand-side?

Answer 6

10 right

Answer 7

good

Answer 8

so now we can factor out the 10 and re-write the equation as follows:\[10\times198=10\times m-10\times2=10\times(m-2)\]

Answer 9

do you understand so far?

Answer 10

little confusing

Answer 11

it might be easier to use an example to illustrate this...
\[10\times3-10\times2=30-20=10\]but this could also have been done in this way:\[10\times3-10\times2=10\times(3-2)=10\times1=10\]

Answer 12

so, in general:\[10\times a-10\times b=10\times(a-b)\]

Answer 13

ok, so are you ready for the next bit?

Answer 14

we got to this point:\[10\times198=10\times m-10\times2=10\times(m-2)\]so we now know:\[10\times198=10\times(m-2)\]next, notice that both left-hand-side and right-hand-side have something multiplied by 10.
so we can divide both sides by 10

Answer 15

my brain is going to pop thanks for your help.

Answer 16

np - just one more step to go and you'll have the answer.

Answer 17

ok

Answer 18

so, if we divide both sides by 10, we get left with:\[198=m-2\]

Answer 19

now, can you see what value m must be?

Answer 20

"something" minus 2 is 198, so that "something" must be equal to?

Answer 21

196

Answer 22

is 196 - 2 = 198?

Answer 23

200

Answer 24

perfect! you got it! :)

Answer 25

I would suggest you practice with lots of problems like this, I'm sure you'll soon get the hang of them

Answer 26

ok got to go are we done?

Answer 27

yes :)

Answer 28

cool thanxs

Answer 29

yw :)