Question

Use Gausses approach to find the following sums
a. 1+2+3+4+...+102

Answer 1

Add the first term,
and the last term,
and multiply by,
the sequence median.

:D

Answer 2

Gauss approach is add forward and backward to get twice the sum . Then divide by two

Answer 3

The median is 51, I'll just go \[\large \sum_{x=1}^{102}x=51(1+102)=5253\]

Answer 4

so 1 +102=103, 2 +101 =1-3, 3+100=103....how long do i use it?

Answer 5

51 times!

Answer 6

Hey Zep can you explain how you got 51?

Answer 7

you dont have to be rude, i had already sent my post before I saw your response

Answer 8

I wasn't rude haha :P

Answer 9

I just want to understand how you got 51 so quickly so i can practice this method :)

Answer 10

As I said earlier, you can simply add up the first term to the second term and multiply this sum by the median of this sequence, and voila!

(Median of the sequence could be found be simply take the last number of the sequence, and divide it by 2)

Answer 11

In this case, you do 102/2 = 51 :)

Answer 12

you mean the first term by the last term and divide by two? so 1+3+5+7+...1001? the sum =502002??

Answer 13

Um, that would be 251 001

Answer 14

(1001+1)/2=501?

Answer 15

501(1+1001)=

Answer 16

Well, these are odd numbers, we can write them as 2n-1 \[\large \sum_{x=1}^{501}2n-1\]

Answer 17

ohhhhhh lol...thank you! i'll keep practicing..

Answer 18

Which is what you got above, divided by 2

Answer 19

"you mean the first term by the last term and divide by two? so 1+3+5+7+...1001? the sum =502002??"

502 002/2 = 251 001 :)

Answer 20

ohh i didnt finish the problem lol