Mathematics
10 Online
OpenStudy (anonymous):
(x-68)^(2/5) = 81. There are apparently multiple answers, and I've only found one (59117.) Please help!
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OpenStudy (anonymous):
Hello there.
OpenStudy (anonymous):
Any ideas?
OpenStudy (anonymous):
-59117?
OpenStudy (anonymous):
Afraid I've already tried that one. I guess I'll give it one more try just for luck.
OpenStudy (anonymous):
well maybe not - it is a fractional root
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OpenStudy (anonymous):
Nope nope nope.
OpenStudy (anonymous):
Yeah, I've no idea how I'm supposed to find the second answer.
OpenStudy (anonymous):
Give up? lol
OpenStudy (anonymous):
haha
OpenStudy (anonymous):
Well...I guess I'll just ask my bf when he comes online. Thank you though!
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OpenStudy (anonymous):
okay, i found a way to graph it online and it doesn't seem like there would be another answer
OpenStudy (anonymous):
Doesn't surprise me. I really should've just gone to a tutoring session.
OpenStudy (anonymous):
yeah, that can help
OpenStudy (anonymous):
Anyway...not to be clingly/overly demanding...but...care to help me with another problem?
OpenStudy (anonymous):
Namely this: x^{3/8} - 12 x^{3/16} + 36 = 0
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OpenStudy (anonymous):
clingy? it's math! not a problem, um... that's... a problem :-P
OpenStudy (anonymous):
I mean...I'm presumably supposed to use substitution.
OpenStudy (anonymous):
So say I replace x^(3/8) with y.
OpenStudy (anonymous):
u - 12u^(1/2) + 36?
OpenStudy (anonymous):
That gives me y - 12y^2 + 36, which is alot less intimidating
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OpenStudy (anonymous):
yep
OpenStudy (anonymous):
Or wait...no. Is it 12y^(1/2)?
OpenStudy (anonymous):
y ^2 would back substitute to x ^(3/4)
OpenStudy (anonymous):
Oh...maybe that's why then...
OpenStudy (anonymous):
Wait...but 3/16 * 2 = 3/8.
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OpenStudy (anonymous):
not if you replace y = x ^(3/8)
OpenStudy (anonymous):
But that wouldn't make sense. Because the object is to substitute another value in for the variable/exponent combination in the middle (i.e. 12x^3/16)
OpenStudy (anonymous):
x^{3/8} - 12 x^{3/16} + 36 = 0
would go to:
y - 12y^2 + 36 = 0
OpenStudy (anonymous):
But 3/8 * 2 doesn't equal 3/16
OpenStudy (anonymous):
oops!
y - 12y^(1/2) + 36 = 0
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OpenStudy (anonymous):
Yeah, but it'd still make more sense to just substitute y^2 for x^(3/8)
OpenStudy (anonymous):
ha!
OpenStudy (anonymous):
but then where does substitution come in?