Question

C array help

Answer 1

i have this code
```
#include <conio.h>
#include <stdio.h>

main()
{
int a[100];
int b, c, d;
printf("How many numbers do you want? ");
scanf("%d", &c);

for (b=1; b<=c; b++)
{
printf("\nEnter number %d: ", b);
scanf("%d", d);
}
getch();
}
```

how can i make the program print the inputted numbers in a form of a list?

Answer 2

#include <conio.h>
#include <stdio.h>

main()
{
int a[100];
int b, c, d[c];
printf("How many numbers do you want? ");
scanf("%d", &c);

for (b=1; b<=c; b++)
{
printf("\nEnter number %d: ", b);
scanf("%d", d[b]);
}

getch();

}
may be this can be helpful

Answer 3

#include <conio.h>
#include <stdio.h>

main()
{
int a[100];
int b, c;
printf("How many numbers do you want? ");
scanf("%d", &c);

for (b=1; b<=c; b++)
{
printf("\nEnter number");
scanf("%d", &a[c]);
}

getch();
}

Answer 4

The &a[c] lets you give an input of c numbers
If you want to display it again
then you can add up the following code
for (b=1; b<=c; b++)
{
printf("\nThe numbers are\n");
printf("%d", a[c]);
}

Answer 5

it will give you array out of bound error ? dont you noticed?

Answer 6

In C an array always starts at index 0, not 1. You can ask the user for the first number but the first position in the array is zero. And the highest index is the size of the array minus 1. 99 in this case. So you should use < instead of <= and starting at 0. Otherwise you could get an index out of range error when accessing index 100.

#include <conio.h>
#include <stdio.h>

main()
{
int a[100];
int b = 0;
int c = 0;

// c mustn't be higher than 100
// if c is greater 100, ask the user again
do {
printf("How many numbers do you want (max. 100)? ");
scanf("%d", &c);
} while(c > 100);

// input
for (b=0; b<c; b++) {
printf("Enter number %d: ", b+1);
scanf("%d", a[b]);
}

// output
for (b=0; b<c; b++) {
printf("Number %d: %d\n", b+1, a[b]);
}

getch();
}