Question

The number N of state and federal inmates in millions during year x, where x >2002 can be approximated by the following formula.
N=0.03x-58.68
Determine the year in which there were 1.5 million inmates.

Answer 1

I don't get that all

Answer 2

set your formula equal to 1.5 and solve for \(x\)

Answer 3

before we continue, would you like to go back to the previous problem?
\[\frac{7}{8}x\geq -\frac{3}{16}\]?

Answer 4

1.5=0.03x58.68
is that set up right?

Answer 5

for the previous one, multiply both sides by \(8\) to get
\[8\times \frac{7}{8}x\geq -\frac{3}{16}\times 8\]
\[\cancel{8}\times \frac{7}{\cancel{8}}x\geq -\frac{3}{\cancel{16}^2}\times \cancel{8}\]
\[7x\geq -\frac{3}{2}\]

Answer 6

then divide both sides by \(7\) to get
\[\frac{7x}{7}\geq -\frac{3}{2\times 7}\]
\[x\geq -\frac{3}{14}\]

Answer 7

for this one, solve
\[1.5=0.03x-58.68\] for \(x\)

Answer 8

add \(58.68\) to both sides to get
\[1.5+58.68=0.03x\]\[60.18=.03x\]

Answer 9

then divide both sides by \(0.03\)

Answer 10

2006 would the year

Answer 11

after dividing both sides by 0.03

Answer 12

yup

Answer 13

now I see how its calculated. thank you!

Answer 14

yw