Write the expression 125m^6 - 8n^3 in factored form.
\[125m ^{6}-8n ^{3}\]
Yeah^
step one....is there any factors of 125 and 8 that are the same?
for example: if the problem was 5m+10m^2 the 5 and the 10 have a factor in common and that is 5
I don't think there's a common factor betweem 125 and 8
Hint: 5³ = 125 and 2³ = 8
5 and 2?
Yeah. Also remember that (a³ - b³) = (a-b) (a²+a b+b²)
okay
so, 125 and 8 have no like factors =)
m is also not n....so same problem
it is either not factorable or she wants the factors for each term
5*5*5*m*m*m*m*m*m-2*2*2*n*n*n
It's factorable...
for instance 5m+10m2 would have been 5m(1+5m) factored
how?
Let m² = p then factor it. Hint: (a³ - b³) = (a-b) (a²+a b+b²)
what formula is that?
the hint one
So would i do this it has nocommon factor
@jwheele1 Perfect Cubic Polynomial http://mathworld.wolfram.com/PerfectCubicPolynomial.html
Let m² = p \[125m^6 - 8n^3 = 125p^3 - 8n^3\] Now factor it.\[125p^3 - 8n^3 = (5p)^3 - (2n)^3 = (5p - 2n)((5p)^2 + (5p)(2n) + (2n)^2)\]
i see.. thank you
I know it looks complicated. Do you understand?
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