A florist stocks red roses and white roses. Of these, some have thorns and some do not. Let R be the event that a rose is red, and let T be the event that a rose has thorns. Suppose that the following data has been collected about the roses: 1/4 of the roses have thorns, 1/5 of the red roses do not have thorns, and 3/7 of roses with thorns are white. Consider the experiment of selecting a rose at random. Use the data to find the probability of each of the four events R ∩ T R ∩ ~T ~R ∩ T ~R ∩ ~T
For the first one I reasoned that you have a 1/4 chance of selecting a rose with thorns and of that 1/4 3/7 of them would be white. The rest of the 4/7 thorned roses must then be red. So I think P(R ∩ T ) = (1/4)*(4/7) = 1/7
Please let me know if you think I did the first one correctly. I'm stuck on the second one
I think for the next one you would have a 1/7 chance of picking a red rose with thorns and a 4/5 of red roses have thorns then you divide this chance by 4 to get the 1/5 chance there are no thorns P(R ∩ ~T ) = (1/7)*(1/4) = 1/28
I think for the next one you know you have 1/4 chance of getting a rose with thorns and also that 3/7 of them are white so P(~R ∩ T ) = (1/4)*(3/7) = 3/28
first one is right
ok that's a good sign
1/5 of the red roses do not have thorns,, doesn't that mean that R ∩ ~T=1/5 ?
it is late and my head is spinning, but with careful thought we can figure out what proportion of the roses are red and anything else you need
even if 1/5 of the red roses don't have thorns don't we need to consider the probability of picking a white rose as well?
I appreciate it satellite :)
hold on one sec, i will see if i can make it clear
For the last one I thought that if you have a 1/4 chance of picking a rose with thorns then 3/4 must not have thorns. Of this 3/4 you have a 1/28 chance of picking a red rose from the second part. This would give you P(~R ∩ ~T) = (3/4)*(27/28) = 81/112
I don't feel very confident about these
ok my brain is shot, but lets try this, and then we can do it correctly with probabilities suppose there are 700 roses, then one fourth of them or 175 have thorns and the rest do not of those 175, 3/7 are white so there are 75 white roses with thorns, and therefore 100 red roses with thorns that is 4/5 of the red roses, so there must be 125 red roses all together of which 100 have thorns and 25 to not
i was doing exactly that ^^
so 2n will be 25/700 = 1/28, so thats correct
so we now now the exact composition of these 700 roses 125 red and 575 white 100 red roses have thorn, 25 do not, 75 white roses have thorns, so 500 do not now you can answer any question
Yes this is perfect. I think I confirmed all my answers except the last one as well
oh sorry i meant \[P(R\cap T^c)=\frac{1}{7}\]
you can redo this without the 700 and see that the answers are the same
wouldn't it be 25/700 or 1/28? for P(R∩~T)
yeah i told you my brain was shot
yup, that i already mentioned
last one comes out to be 500/700 = 5/7... ?
last one would be \(\frac{5}{7}\) i think white without thorns try repeating the same computation without the 700
over and out
thanks again satellite! :D
not red and thorns = white and thorns = 75/175= 3/7
1/7,1/28,3/7,5/7
wouldn't it be 75/700 or 3/28?
but there are only 175 flowers with thorns....
oh, wait, its 75/700,sorry
but you need the probability of choosing from all 700. You aren't guaranteed to get one with thorns
yeah
i also get confused with this
I just don't know how to reason my way through the last one to get 5/7
you have a 3/4 chance to get a rose without thorns
how do you turn that into 5/7?
ah I got it. It's 3/4 chance minus the 1/28 chance you get a red one. So (3/4)-(1/28) = 5/7
or 2/7 with thorns are red, so all others are 1-2/7 = 5/7
yeah that works too
thanks for your help as well hartnn!
even i learned this....its been some time i haven't done such problems....
all thanks to satellite
It's my first time taking statistics, so this is all new to me haha
I still appreciate you taking you time to take a look at this problem anyways
no problem ^_^
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