Question

Find the slope of the normal line to the graph of f(x)=sqrt(2x+1)+cos(pi*x) at the point where x=4.

Answer 1

I've attached my work so far. Where should I go from here?

Answer 2

f(x)=sqrt(2x+1)+cos(pi*x) at the point where x=4
\[f'(x)=\frac{ 1 }{ \sqrt{2x+1} }+\pi \sin \pi x\]

slope m at x=4
\[m=\frac{ 1 }{ 3 }-\pi \sin 4 \]
m=1/3 ans...

Answer 3

im sorry that is
m=1/3 - pi sin 4pi
m=1/3

Answer 4

Ah, thanks. I had a misstep there with the chain rule.