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If x^2+y^2=25 then find an expression for y'' Steps please, so i can compare to mine to see if i did this correct? I have a quiz tmr. I got (25/y^3) but i have a feeling i messed up on a sign somewhere.
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i just need the steps for the second part where we find y'' and plug in the -25 at the end
\[2xx'+2yy'=0\] \[y'=-\frac{xx'}{y}\] and then repeat
im asking for specifics :3 lol i know the deriv. rules
Derivative with respect to x?
no to y
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\[25-x ^{2} = y ^{2}\] \[y = \sqrt{25 - x ^{2}}\]
no you're looking for derivative with respect to y. it says y'' at the top. maybe you misunderstood what i was asking :o
respect blahhhh to x.. typo -_-
the second derivative
|dw:1348804505243:dw| hmm this is what i came up with
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