Question

complete the square

(4(x-2)/x-3)+3/x=-3/x(x-3)

Answer 1

the denominator will be x(x-3)

Answer 2

(4(x-2)/x-3)+3/x=-3/x(x-3
\[\frac{ 4(x-2) }{ x-3 }+\frac{ 3 }{ x }=\frac{ -3 }{ x(x-3) }\]

Answer 3

\[\frac{ 4x(x-2)+3(x-3) }{ x(x-3)}=\frac{ -3 }{ x(x-3) }\]

Answer 4

\[\frac{ 4x^{2}-8x+3x-9 }{ x(x-3) }=\frac{ -3 }{ x(x-3) } \]

Answer 5

now cancelling both the denominator
\[4x ^{2}-5x-6=0\]

Answer 6

(4x+3)(x-2)=0