Consider a 8.0-kg red block pressed against a wall falling at -2.5 m/s. Given the following coefficients between the wall and the block--μk = 0.4 and μs = 0.7, determine the force of the hand that acts on the block. Use g = 9.79 m/s

Question

anonymous · Answer

i think it shuld be --2.5 m/s^2

anonymous · Answer

How did you determine that? I was looking around on yahoo answers and someone suggested using mg=uF

anonymous · Answer

m/s = Velocity

m/s^2 = accl.....

anonymous · Answer

here -2.5 indicate...that  the wall is falling opposite to the Direction of Force Appl

anonymous · Answer

$$F-\mu mg = ma $$

anonymous · Answer

$$F = m(\mu g + a)$$

anonymous · Answer

I think here u have to Use...Kinetic Since The Wall is Moving..)

anonymous · Answer

I mean Kinetic Friction.....Try this out...@dimex001

anonymous · Answer

I misread your acceleration comment and I think you might be right. I was confused it I was supposed to somehow use both coefficients but it makes sense to use the kinetic friction since its moving.

anonymous · Answer

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