Question

integrate (cscx)^3

>_>

Answer 1

integration by parts it will work

Answer 2

int (cscx)^3 = int (cscx)^2 cscx dx
let u=cscx
du=....
dv=(cscx)^2 dx
v=int(cscx)^2 dx
v=.....
and next use parts rule : int(udv) = uv-int(vdu)

Answer 3

but i was stuck to find int(cscx) dx, @TuringTest ^^
lol

Answer 4

i'm not sure int (cscx)dx = ln(sinx)

Answer 5

@RadEn
OpenStudy values the Learning process - not the ‘Give you an answer’ process •Don’t post only answers - guide the asker to a solution.
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Answer 6

\[ \int \csc ^3xdx = \int (1 + \cot^2 x) \csc x \; dx\]

Answer 7

is there another trig identity i'm supposed to use? u-substitution isn't working

Answer 8

There is something of a trick to this... try
\[\int \frac{ \sin(x)}{\sin^2(x) } dx\]

Answer 9

i'm not sure how you got that

Answer 10

its not (cosx)^2 / (sinx)^3?

Answer 11

I'm talking about integrating cosecant.

Answer 12

use the same technique as used here
http://en.wikipedia.org/wiki/Integral_of_secant_cubed