Question

hello every one can you solve this equation
11/4 over m+4=7 over m+4

Answer 1

is your problem this:
(11/4)/m + 4 = 7 / (m+4)

Answer 2

this is the equation 1-1/4 over m+4=7/m+4

Answer 3

not 11

Answer 4

Can you put your equation with parenthesis such that I can better understand your order of operations?

Answer 5

wait

Answer 6

\[1\frac{ 1 }{ 4 }=\frac{ 7 }{ m+4 }\]

Answer 7

thats wrong

Answer 8

thats wrong
\[1-\frac{ 1 }{ 4 }=\frac{ 7 }{ m+4 }\]

Answer 9

is that right?

Answer 10

yes,all equation is over m+4

Answer 11

alright then... lets begin by simplifying the right side of the equation.
What is 1 - (1/4) ?

Answer 12

hello kwo8 those first equation is over m+4

Answer 13

ok

Answer 14

therefore, your problem is:
((1-(1/4))/(m+4)) = 7/(m+4)

Answer 15

I hope I am getting this problem correct because I can't start until I'm sure i've got the problem right.

Answer 16

kwo8 you asked me what is 1(1/4) i just know is 4/4
because i multiply 4 into 1 angd divide 4 to one

Answer 17

lets go back to the first step. I want to reconfirm that your original problem is ((1-(1/4))/(m+4)) = 7/(m+4)

Answer 18

thats right

Answer 19

I would like to comment that this problem is very strange. That is because there is m+4 on both sides of the equation. This means that you can cancel it out... rendering this problem meaningless to solve. Are you sure this is right!?

Answer 20

sorry kwo8 if i'm interupting you and increase the problem

Answer 21

yes i'm sure

Answer 22

it might be
\(\huge1-\frac{1/4}{m+4}=\frac{7}{m+4}\)

Answer 23

good point... is hartnn correct?

Answer 24

if not please take the snapshot of question and post

Answer 25

kwo can you see those equation by hartnn that correct

Answer 26

hello hartnn those equation is correct

Answer 27

ok... we can start solve the problem now that we have it.
First you should move all numbers related to 'm' to one side of the equation.
This means that you will have to move (1/4)/(m+4) to the right side of the equation. What operation are you doing now? (subtraction? addition? division? multiplication?)

Answer 28

multiplycation

Answer 29

nope...