A cylindrical can is to be constructed to hold 400cm^3 of liquid. The cost of the material for the circular top and bottom of the can is 3 cents per square centimeter and the cost of the material used for the curved sides is 2 cents per square centimeter. Find an eqn for the cost, C, in terms of the top and bottom, r, and the height of the can, h.

Question

ajprincess · Answer

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The cost of the material for the circular top and bottom of the can=2*pi*r^2*3
The cost of the material used for the curved sides=2*pi*r*h*2
Total cost c=6*pi*r^2+4*pi*r*h
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pi=400/(r^2*h)
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Is it clear?