Question

restrictions for (a-c)/(x-a)=m, solve for x?

Answer 1

\[\frac{a-c}{x-a}=m\]
Multiply both sides by x-a
then u get
\[\frac{a-c}{x-a}*(x-a)=m*(x-a)\]
\[a-c=m(x-a)\]
Divide both sides by m.
\[\frac{a-c}{m}=\frac{m(x-a)}{m}\]
\[\frac{a-c}{m}=x-a\]
Add a both sides
\[\frac{a-c}{m}+a=x-a+a\]
\[\frac{a-c}{m}+a=x\]
\[\frac{a-c+ma}{m}=x\]
Is it clear?

Answer 2

Your answer is clear, just not what I'm looking for. I know the answer for it already, but I'm supposed to "State any restriction on the variables" but I don't understand what that means.

Answer 3

Restriction is \(m\ne0\).
When m=0 the equation becomes equal to infinity.

Answer 4

Ohhh, okay. That makes more sense now. Thank you very much. That helped.

Answer 5

yw:)

Answer 6

Also \(x-a\ne0\)